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Deepak Kumar Singh 15

# Print duplicates and its occurrences in the array ? Solution required urgently !!! e. Print duplicates and its occurrences in the array (for ex: if array is [2,2,3,4,4,5] then your output will be as follows : Number : Appearance 2 : 2 3: 1 4 :2

Best Answer chosen by Deepak Kumar Singh 15
charchit nirayanwal
use map

public class thecodeclass {
public static void main(){
list<integer> listt=new list<integer>{2,3,2,2,4};
map<integer,integer> amap=new map<integer,integer>();
for(integer a:listt){
if(amap.get(a)<>null){
amap.put(a, amap.get(a)+1);}
else{
amap.put(a,1);
}
}
system.debug(amap);
}
}

charchit nirayanwal
use map

public class thecodeclass {
public static void main(){
list<integer> listt=new list<integer>{2,3,2,2,4};
map<integer,integer> amap=new map<integer,integer>();
for(integer a:listt){
if(amap.get(a)<>null){
amap.put(a, amap.get(a)+1);}
else{
amap.put(a,1);
}
}
system.debug(amap);
}
}
This was selected as the best answer
Suraj Tripathi 47
Hi Deepak Kumar Singh
public class FindDuplicate {
public static void countDuplicate(){
List<Integer> numList = new List<Integer>{2, 2, 3, 4, 4, 5};
Map<Integer, Integer> countDuplicateMAp = new Map<Integer, Integer>();
for(Integer each : numList){
countDuplicateMAp.put(each, countNumber(each, numList));
}
system.debug('countDuplicateMAp : '+ countDuplicateMAp);
}
public static Integer countNumber(Integer DigNum, List<Integer>numerList){
Integer countNum = 0;
system.debug('DigNum : '+ DigNum);

for(Integer val : numerList){
system.debug('valu : '+ val);
if(val == DigNum){
++countNum;
}
}
return countNum;
}
}
I hope you find the above solution helpful.
If it does, please mark as Best Answer to help others too.
Thanks and Regards,
Suraj
Priya Singh 118
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