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Trif Cristian 7 How can I remove HTML content attributes in Java/APEX?
I want to remove from my regex all content for my attributes. Below I have my regular expression and I want to happen is to, for example, I have this: style=" padding:0cm 0cm 0cm 0cm" this is an HTML attribute and I want to remove what's inside the "" which is the content. So from style="padding:0cm 0cm 0cm 0cm" I want to be only style=""; and also from
style="font-family:"Open Sans",sans serif;color:#444444" to be only style=""....Can I remove my attribute content with regexp?
regexpStart = '(?<=Name:<o:p></o:p></span></p>###LB###</td>###LB###<td
style="padding:0cm 0cm 0cm 0cm">###LB##';
regexpStart += '#<p class="MsoNormal" style="line-height:18.0pt;mso-line-
height-rule:exactly"><span style="fon';
regexpStart += 't-family:"Open Sans",sans serif;color:#444444">)';
regexpEnd = '(?=<o:p>)';
regexp = regexpStart + '.*?' + regexpEnd;
https://stackoverflow.com/questions/48251198/regex-pattern-to-replace-html-in-a-given-text-string
https://regexr.com/
https://www.regextester.com/1946
string regexpStart = '(?<=Name:<o:p></o:p></span></p>###LB###</td>###LB###<td style="padding:0cm 0cm 0cm 0cm">###LB##'; regexpStart += '#<p class="MsoNormal" style = "line-height:18.0pt;mso-line-height-rule:exactly"><span style ="fon'; regexpStart += 't-family:"Open Sans",sans serif;color:#444444">)'; string regexpEnd = '(?=<o:p>)'; string regexp = regexpStart + '.*?' + regexpEnd; system.debug(regexp); string regexp2 = regexp.replaceAll('style([^=]*?)=([^"]*?)\".+?\"','style=\"\"'); system.debug(regexp2); string regexp3 = regexp.replaceAll('style[ ]*?=[ ]*?\".+?\"','style=\"\"'); system.debug(regexp3);