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loneboat I have a JSON string which represents a List<String>, but I can't figure out how to deserialize it - I don't know what to put for the deserialization type argument.
List<String> myList = (List<String>)System.JSON.deserialize(json_string, ????);
I've tried putting "List<String>" as the arg, but I get an error about an "unexpected token".
This works:
(List<String>)System.JSON.deserialize(json_string, List<String>.class)
All Answers
This works:
(List<String>)System.JSON.deserialize(json_string, List<String>.class)
I am new to REST API and am getting error on JSON deserialization :I tried the above solution, but NOT think i am doing it correctly:
Could you pl have a look and tell me how shall i go about.
I am doing :---In the workbench : POST Method : I am using the below data:
{"merch" : [ {"name" : "Eraser1", "description" : "desc", "price" : 2}, {"name" : "Eraser2", "description" : "desc", "price" : 20}, {"name" : "Eraser3", "description" : "desc", "price" : 28} ]}and it Errors with :
[ { "message" : "Expected JSON object to deserialize apex parameter from at [line:2, column:2]", "errorCode" : "JSON_PARSER_ERROR" } ]Could you plz guid :
@HttpPost global static String createMerchandise(String merch) { List<Merchandise__c> tt = (List<Merchandise__c>)System.JSON.deserialize(merch, List<Merchandise__c>.class); system.debug(tt); // this is just to see how the data would look }"message": "JSON request body must be an object at [line:1, column:2]",
"errorCode": "JSON_PARSER_ERROR"
What was the fix?
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(List<String>)System.JSON.deserialize(json_string, List<String>.class)
List<String> testData= (List<String>)JSON.deserialize(req.requestBody.toString(), List<String>.class);
//In Test Class, initialize a List.
List<String> strList = new List<String>();
//Now initialize a String
String str = 'Test String';
strList.add(str);
//Pass this list to request body
request.requestBody = Blob.valueof(JSON.serialize(strList));