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crocodile !!!!Record is not inserted!!!!
Hi all,
I have two objects prac__c, Dept__c.
I wrote a trigger for prac__c which calls a method m1() in pracs_prac1.class when a record is created/updated in prac__c object
Apex class shown below:
public class pracs_prac1 {
public static void m1(prac__c[] a1)
{
Dept__c dpt=new Dept__c(Name='testing');
try
{
insert dpt;
}
catch(DMLException e)
{
system.assert(false,'Error creating Calc:'+e.getDMLMessage(0));
}
}
}
This class is compiled successfully without any error.
But when i created a record in prac__c no record is inserted in Dept__c
Is there any createable property set to be true?
when i used the statement: Dept__c.createable=true; in the above class getting an error saying Save error: Variable does not exist: Dept__c.createable
then how can i set the createable property to true?
Is there any code i have to use apart from this? Please help me in this regard.
Thanks in advance,
-Vissu
I have two objects prac__c, Dept__c.
I wrote a trigger for prac__c which calls a method m1() in pracs_prac1.class when a record is created/updated in prac__c object
Apex class shown below:
public class pracs_prac1 {
public static void m1(prac__c[] a1)
{
Dept__c dpt=new Dept__c(Name='testing');
try
{
insert dpt;
}
catch(DMLException e)
{
system.assert(false,'Error creating Calc:'+e.getDMLMessage(0));
}
}
}
This class is compiled successfully without any error.
But when i created a record in prac__c no record is inserted in Dept__c
Is there any createable property set to be true?
when i used the statement: Dept__c.createable=true; in the above class getting an error saying Save error: Variable does not exist: Dept__c.createable
then how can i set the createable property to true?
Is there any code i have to use apart from this? Please help me in this regard.
Thanks in advance,
-Vissu
I might be wrong but may be field is spelled differently in your object.
Thanks for ur reply.
My trigger code:
trigger pracs_trig1 on prac__c (before insert, before update)
{
prac__c[] a1=trigger.new;
pracs_prac1.m1(a1);
}
First of all i want to insert a record named testing. After successful insertion i wan to pass the values for the fields.
-Vissu
Thanks for ur reply.
createable is not a field.
In http://www.salesforce.com/us/developer/docs/apexcode/index.htm there is a statement like
"To create an sObject record, the createable property of the sObject must be set to true"
So, i tried to set createable property to true using the code:
Dept__c.createable=true;
Then getting an error saying: Save error: Variable does not exist: Dept__c.createable
Any idea to rectify this error...?
-Vissu