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paul-lmipaul-lmi 

sorting a list of non-primitives

In the apex documentation, it says that the sort method for a list can only be used if the list is of primitive types.  Does anyone know of a way to work around this with non-primitive types?

 

I'm building a YouTube integration, and I bind the API results to a custom data type called "video", and I'd like to sort by one of the properties of the video when I have a list of them.

BritishBoyinDCBritishBoyinDC

This post might help - bascially, it uses maps to sort lists...

 

http://community.salesforce.com/t5/Apex-Code-Development/A-gift-for-you-Sorting-a-List-lt-sObject-gt/m-p/107833

 

 
TehNrdTehNrd

Also check this out: http://blog.sforce.com/sforce/2008/09/sorting-collect.html

 

I use this method all the time.
miteshsuramiteshsura

Hi,

 

You may have already found an solution to this, but I thought I would post this anyways, as it may benift others.

 

I was some r&d on the same lines, and stumbled upon the post previous user mentioned. But it was too much for what I wanted to do.

 

Instead of a list<sObject> to order, I have a list<WrapperClass> to sort, which is not much different when it comes to sorting.

In the wrapper class I had custom Object, boolean, and sort order fields.

 

What I did was iterate original non-primitieve list I wanted to sort, and copied just the field "sortOrder" into new list<integer>, lets say list<integer>

 

list<integer> mySortOrder = new list<integer>();

for(list<non-primitive> y : orginalList){

   mySortOrder.add(y.sortOrder);

}

//Once I had that, I invloded

mySortOrder.Sort();

 

Than I have two for loops:

Outter for loop --> iterate over mySortOrder

Inner for loop --> iternate over org list I wanted to sort

 

for(integer x : mySortOrder){

  for(list<non-primitive> y : orginalList){

 

  if(x == y.sortOrder){

 

   // Your business logic //

 

   }

 

  }

}

 

Depending on your needs, you may want to add some validation. Works great for our needs, and very simple. I have not tested on huge set, but works good for 100-200 records in the list.

 

Tthought someone can take advantage of this.

 

regards

Mitesh