I have two record types name as Doctor and Other.

How to achieve the Record type IDs in test class to achieve step1 controller?

Error:-  System.QueryException: List has more than 1 row for assignment to SObject

Stack trace:- Class.newpatientController.testnewpatientController: line 72, column 1

public class newpatientController {

Patient__c patient;
Contact contact;
Order__C order;

public Contact getContact() {
if(contact == null) contact = new Contact();
return contact;
}

public Patient__c getpatient() {
if(patient == null) patient = new Patient__c();
return patient;
}

public Order__C getorder() {
if(order == null) order = new Order__C();
return order;
}

public PageReference step() {
return Page.recordtype;
}



public PageReference step1() {
if(Patient.RecordTypeId=='01290000000SNs1AAG')
{
return Page.newdoctor;
}
else
{
return Page.newpatient;
}
}

public PageReference step2() {
return Page.newpatient2;
}

public PageReference step3() {
return Page.newpatient3;
}

public PageReference save() {


insert patient;
system.debug('--------------------------------------------'+patient.id);


contact.Patient__c= Patient.id;
insert contact;

order.Patient_Name__c= patient.id;
insert order;

PageReference orderPage = new PageReference('/' +order.id);
orderPage.setRedirect(true);

return orderPage;
}
private static testmethod void testnewpatientController(){
newpatientController controller = new newpatientController ();

Patient__C pat = new Patient__C(id='a0a90000000SbUN');
id idRT = [select Id from RecordType where SobjectType = 'Patient__c' ].Id;
pat.RecordTypeId = idRT;
pat.Name = 'a0a90000000SbUN';

Order__C ord = new Order__C(id='a0Z9000000C5bNx');
ord.Patient_Name__c = 'a0a90000000SbUN';
ord.Type_of_Study__c = 'Sleep';
ord.Date_of_Study__c = Date.newInstance(2010,12,31);

Contact cont = controller.getContact();
cont.LastName = 'Testlast';
cont.FirstName = 'name1';
cont.phone = '5551211234';

controller.step();
controller.step1();
controller.step2();
controller.step3();
controller.save();
}
}

Thanks In advance.