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Meer Salman output link value?
Hi,
This is a bit complicated issue so let me write in steps:
1) I created a Custom Object and overide its Detail View and New page by my own VFPages.
2) I wanted to have another header tab for the same object so I created a VFPage and add it as a tab by name 'Payment Journal'. It is as similar as the default tab layout of the custom object, however there are few changes.
3) In 'Payment Journal' Tab I have a pagetable in which some particular records are shown with their 'Name' in outputlink tag.
4) I want to show another VFPage for Detail Veiw when the outputlink is clicked.
5) I guess this can be done by giving the value to output link but I am not exactly getting how to give a value in this case.
NOTE: Remember I already have overidden the Detail Veiw thus, there are two Detail Veiw pages.
Hope it is clear now, Please help me in this I shall be very thankful.
It was a bit simple all what to do is simply put the URL
<apex:outputlink action="paste the link here with Page Name?{!accs.Id}&sfdc.override=1">{!accs.Name}</apex:outputlink >
All Answers
Hi Meer,
You can try the following:
<apex:page controller="SampleController">
<apex:form >
<apex:dataList value="{!accList}" var="accs">
<apex:commandLink action="/{!accs.Id}" value="{!accs.Name}"/> --- This renders the account Name as link and on click of the Name user will be redirected to the corresponding Account detail page.
</apex:dataList>
</apex:form>
</apex:page>
Hope this helps.
Thanks
Sureka
No dude this is not what I want. I know what are you saying but its not the right answer.
It was a bit simple all what to do is simply put the URL
<apex:outputlink action="paste the link here with Page Name?{!accs.Id}&sfdc.override=1">{!accs.Name}</apex:outputlink >