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dmattivi1.3948969980392463E12
How to show an object page layour if a specific condition is met
Hi,
I'm pretty new in SF development and I would like to perform the following : when an opportunity is changing the status to closed won, I would like to show the page layout of a custom object. I've written the following Apex code (for my test I imagine that my custom object is Account object), it seems that my condition is good but the account page doesn't display. Could you please help me ?
Didier
Here is my code
trigger Action_on_Closed_Won on Opportunity (after update)
{
Opportunity ops_new = Trigger.new[0];
Opportunity ops_old = Trigger.old[0];
if ( ops_new.IsWon && !ops_old.IsWon )
{
System.debug( 'Before Account' );
Account a = new Account();
System.debug( 'After Account' );
}
else
{
System.debug( 'Else' );
}
}
I'm pretty new in SF development and I would like to perform the following : when an opportunity is changing the status to closed won, I would like to show the page layout of a custom object. I've written the following Apex code (for my test I imagine that my custom object is Account object), it seems that my condition is good but the account page doesn't display. Could you please help me ?
Didier
Here is my code
trigger Action_on_Closed_Won on Opportunity (after update)
{
Opportunity ops_new = Trigger.new[0];
Opportunity ops_old = Trigger.old[0];
if ( ops_new.IsWon && !ops_old.IsWon )
{
System.debug( 'Before Account' );
Account a = new Account();
System.debug( 'After Account' );
}
else
{
System.debug( 'Else' );
}
}
Eli Flores, SFDC Dev
Search for 'saveURL' here and you'll get heaps of information about how to do this. :)