Apex Code Development You need to sign in to do that
Don't have an account?
Disable and Enable Custom button
Hello All,
I have one custom button in custom object view details page. I want enable or disable button based on condition whether current record exits on another custom object. Is is possible ? if so please suggest some steps to do
I have one custom button in custom object view details page. I want enable or disable button based on condition whether current record exits on another custom object. Is is possible ? if so please suggest some steps to do
It is not possible.
Have a look on record type may be that will give you an idea.
Because using Record type you can have different page Layouts.
Record Types Overview
https://help.salesforce.com/HTViewHelpDoc?id=customize_recordtype.htm
Creating Record Types
https://help.salesforce.com/HTViewHelpDoc?id=creating_record_types.htm&language=en_US (https://help.salesforce.com/HTViewHelpDoc?id=creating_record_types.htm&language=en_US)
How is record type access specified?
https://help.salesforce.com/HTViewHelpDoc?id=permissions_record_type_access.htm&language=en_US (https://help.salesforce.com/HTViewHelpDoc?id=permissions_record_type_access.htm&language=en_US)
Administrator tip sheet: Tips & Hints for Record Types
https://na1.salesforce.com/help/pdfs/en/salesforce_recordtypes_cheatsheet.pdf
Don't forget to select best answer to make our efforts visible in the developer forum.
Please mark this as solution by selecting it as best answer if this solves your problem, So that if anyone has this issue this post can help
In your page:
<apex:commandButton action="{!youmethod}" value="ButtonName" disabled="{!isBtnDisabled}"/>
On your controller class, create a property isBtnApplyVisible which has to be filled in the constructor method of the controller.
Hoping this solution will help you...